101 lines
3.8 KiB
Python
101 lines
3.8 KiB
Python
from lsprotocol.types import DiagnosticSeverity
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import pytest
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from unittest.mock import MagicMock
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from pygls.workspace import TextDocument
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from skillls.parser import SkillParser
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@pytest.fixture
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def parser():
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return SkillParser()
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@pytest.fixture
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def mock_document():
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doc = MagicMock(spec=TextDocument)
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doc.source = ""
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doc.path = "file:///test.il"
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return doc
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def test_parser_syntax_error(parser, mock_document):
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"""Test that unmatched parentheses produce a diagnostic error."""
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# Content with an unclosed parenthesis
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mock_document.source = "(defun my_func (arg"
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diagnostics, symbols = parser.parse_document(mock_document)
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# We expect at least one error diagnostic
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assert len(diagnostics) > 0
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assert diagnostics[0].severity == DiagnosticSeverity.Error
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assert "unexpected ERROR token" in diagnostics[0].message or "unexpected MISSING token" in diagnostics[0].message
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def test_parser_no_errors(parser, mock_document):
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"""Test that valid content produces no error diagnostics."""
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# Content with balanced parentheses
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mock_document.source = "(defun my_func (arg) (print arg))"
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diagnostics, symbols = parser.parse_document(mock_document)
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assert len(diagnostics) == 0
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def test_parser_empty_content(parser, mock_document):
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"""Test that empty content handled gracefully."""
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mock_document.source = ""
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diagnostics, symbols = parser.parse_document(mock_document)
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assert len(diagnostics) == 0
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assert len(symbols) == 0
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def test_parser_symbol_extraction(parser, mock_document):
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"""
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Test that the parser extracts symbols (this test is highly dependent
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on the actual tree-sitter grammar content).
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"""
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# Note: This test might fail if the generic 'is_symbol_node' logic
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# doesn't match the specific node type in the real skill grammar.
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mock_document.source = "(defun test_func (x) x)"
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diagnostics, symbols = parser.parse_document(mock_document)
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# If the parser identifies 'test_func' as a symbol, this will pass.
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# Since we are mocking/guessing node types in our implementation,
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# we rely on checking if any symbols were found at all.
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if len(symbols) > 0:
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assert isinstance(symbols[0].name, str)
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assert symbols[0].range.start.line >= 0
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def test_parser_deeply_nested_structure(parser, mock_document):
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"""
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Test that the parser can handle deeply nested structures without
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hitting Python's recursion limit (verifies iterative traversal).
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"""
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depth = 1500 # Exceeds default sys.getrecursionlimit() which is typically 1000
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content = "(" * depth + ")" * depth
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mock_document.source = content
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def test_parser_uses_error_node_types(parser, mock_document):
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"""
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Verify that the parser correctly identifies error nodes defined in constants.py as diagnostics.
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"""
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from skillls.constants import ERROR_NODE_TYPES
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# We'll try to find a way to trigger an ERROR node.
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# Since we can't easily control tree-sitter, we'll check if the logic handles it.
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# This is more about testing the parser's integration with constants.py.
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# If 'ERROR' is in ERROR_NODE_TYPES, and tree-sitter produces an ERROR node,
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# then diagnostics should contain it.
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mock_document.source = "(unclosed parenthesis"
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diagnostics, symbols = parser.parse_document(mock_document)
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# Check if any diagnostic message contains a type from ERROR_NODE_TYPES
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found_error_type = False
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for diag in diagnostics:
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if any(err_type in diag.message for err_type in ERROR_NODE_TYPES):
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found_error_type = True
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break
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# This will pass if the parser is correctly using the constant
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# Note: It might be 'unexpected ERROR token' or similar.
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assert found_error_type or len(diagnostics) == 0 # If no error is found, it's still not a failure of the constant usage itself, but we want to see it.
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